Question

In ∆ ABC , ∠A = 76°,∠B = 48°, ∠ C = ?​

Answer 1

Answer:

∠ C=56°

Step-by-step explanation:

in ∆ ABC= ∠A+ ∠B+ ∠ C= 180°

(angle sum property of a triangle)

so ∠ C=180°- (∠A+ ∠B)

∠ C=180-(76+48)

∠ C=180-124

∠ C=56°

hope this helps u

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Answer 2

$\huge \bold \color{green}{ \underline{ \underline \red{required \: answer :- }}}$

in ∆ABC

given :-

$\angle \: A \: = 76 \degree \\ \angle \: B = 48 \degree \: \\ \angle \: C = ?$

$\huge \bold{ \underline{ \underline{concept : }}}$

sum of angle of a triangle are 180°( angle sum property of a triangle)

so in triangle ABC

$\angle \: A + \angle \: B + \angle \: C = 180 \degree \\ \implies \: 76 + 48 + \angle \: C = 180 \\ \implies \: 124 \: + \angle \: C = 180 \\ \implies \: \angle \: C = 10 - 124 \\ \implies \: \angle \: C = 56 \degree$

hence, value of angle C is 56°