derive the expression of potential energy of an object raised by height 'h' above the ground
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1
Answer:
If a body is taken from the surface of the earth to a point at a height ‘h’ above the surface of the earth, then ri = R and rf = R + h then,
ΔU = GMm [1/R – 1/(R+h)]
ΔU = GMmh/R(R + h)
When, h<<R, then, R + h = R and g = GM/R2.
On substituting this in the above equation we get,
Gravitational Potential Energy ΔU = mgh
Explanation:
Answered by
0
Answer:
W= F.dx
W=(mg)×h×cos180
W= -mgh
∆U=mgh
Explanation:
W= -∆U
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