Derive the formula for adding resistors in parallel and series connection.
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in series
since in series current remains the same and voltage changes
V1=IR1
V2=IR2
V3=IR3
add all three of them
IR=IR1+IR2+IR3
IR=I(R1+R2+R3) I as common
R=R1+R2+R3.....so on (LHS I was cut by the I on RHS)
for parallel
in parallel we know that voltage remains the same but current changes
I1=V/R1
I2=V/R2
I3=V/R3
now add them
V/R=V/R1+V/R2+V/R3
V/R=V(1/R1+1/R2+1/R3) v was taken common
R=1/R1+1/R2+1/R3.....so on (v was cut on both sides )
since in series current remains the same and voltage changes
V1=IR1
V2=IR2
V3=IR3
add all three of them
IR=IR1+IR2+IR3
IR=I(R1+R2+R3) I as common
R=R1+R2+R3.....so on (LHS I was cut by the I on RHS)
for parallel
in parallel we know that voltage remains the same but current changes
I1=V/R1
I2=V/R2
I3=V/R3
now add them
V/R=V/R1+V/R2+V/R3
V/R=V(1/R1+1/R2+1/R3) v was taken common
R=1/R1+1/R2+1/R3.....so on (v was cut on both sides )
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