Question

derive the formula for kinetic energy​

Answer 1

$\huge{\mathfrak{Kinetic\:energy}}$

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Derivation-

Kinetic energy=F*S

Initial velocy of body=v

Final velocity=0

Acceleration=-a

Distance travelled=S

Putting te value on equation of motion

${v}^{2} = {u}^{2} + 2as \\ {0}^{2} = {v}^{2} - 2as \\ {v}^{2} = 2as$

From newton 2nd law of motion

F=m*a

a=F/m

Putting the value of acceleration in above equation.

${v}^{2} = \frac{2 \times f \times s}{m} \\ f \times s = \frac{1}{2 }m {v}^{2}$

We know, kinetic energy is F*S

Kinetic energy =1/2mv^

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Answer 2

❤❤Høla mate ❤❤


⏬Answere is here ⏬


Kinetic energy=F*S

Initial velocy of body=v

Final velocity=0

Acceleration=-a

Distance travelled=S

Putting te value on equation ofmotion

\begin{lgathered}{v}^{2} = {u}^{2} + 2as \\ {0}^{2} = {v}^{2} - 2as \\ {v}^{2} = 2as\end{lgathered}v2=u2+2as02=v2−2asv2=2as​

From newton 2nd law of motion

F=m*a

a=F/m

Putting the value of acceleration inabove equation.

\begin{lgathered}{v}^{2} = \frac{2 \times f \times s}{m} \\ f \times s = \frac{1}{2 }m {v}^{2}\end{lgathered}v2=m2×f×s​f×s=21​mv2​

We know, kinetic energy is F*S

Kinetic energy =1/2mv^

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