Derive the formula of kinetic and potential energy ?
Answers
It is clear that the work done is equal to the change in the kinetic energy of an object. If u = 0, the work done will be W =12mv2 W = 1 2 m v. Since workdone on the object is equal to mgh, an energy equal to mgh units is gained by the object . This is the potential energy (Ep) of the object.
Answer:
Explanation:Derivation for the equation of Potential Energy:
Let the work done on the object against gravity = W
Work done, W = force × displacement
Work done, W = mg × h
Work done, W = mgh
Since workdone on the object is equal to mgh, an energy equal to mgh units is gained by the object . This is the potential energy (Ep) of the object.
Ep = mgh
Derivation for the equation of Potenstial Energy:
Let the work done on the object against gravity = W
Work done, W = force × displacement
Work done, W = mg × h
Work done, W = mgh
Since workdone on the object is equal to mgh, an energy equal to mgh units is gained by the object . This is the potential energy (Ep) of the object.
Ep = mgh
Derivation for the equation of Kinetic Energy:
The relation connecting the initial velocity (u) and final velocity (v) of an object moving with a uniform acceleration a, and the displacement, S is
v2 - u2 = 2aS
This gives
S =
v
2
-
u
2
2a
We know F = ma. Thus using above equations, we can write the workdone by the force, F as
W = ma
×
(
v
2
-
u
2
2a
)
or
W =
1
2
m(
v
2
-
u
2
)
If object is starting from its stationary position, that is, u = 0, then
W =
1
2
m
v
2