Question

derive the formula of kinetic energy??...

Answer 1

$\frac{1}{2 } \times mv {}^{2}$

Answer 2

Hii Sapna.



your Ans is

From equations of motion, the relation connecting the initial velocity (u) and final velocity (v) of an object moving with a uniform acceleration a, and the displacement, s is But from Newton’s second law of motion F = m a. work done by the force, F is written as

$w = ma \frac{v {}^{2} - u {}^{2} }{2a} = w = \frac{1}{2} m \: ( {v}^{2} - {u}^{2})$
if the following:

If the object is starting from its stationary position, that is, u = 0, then

$w = \frac{1}{2}m( {v}^{2} - {o}^{2}) = \: w = \frac{1}{2} m {v}^{2}$
From work and energy theorem, work done is equal to the change in the kinetic energy of the object. w = (1/2) mv 2 If u = 0, the work done will be, Thus the kinetic energy possessed by an object of mass, m and moving with a uniform velocity, v is K.E = (1/2) mv 2



Derive f the equation for kinetic energy? Derive f the equation K.E = ½ m v 2