Physics, asked by Amretha, 1 year ago

derive the grahams law of diffusion

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Answered by Anonymous
4
Graham's law of effusion sometimes called Graham's law of diffusion was formulated by Scottish physical chemist Thomas Graham Graham found experimentally that the rate of effusion of a gas is inversely proportional to the square root of the mass of its particles

Amretha: derivation
Answered by Anonymous
2

Answer:

Graham's law of diffusion :-

This law states that, 'At constant temperature and pressure, the rate of diffusion of various gases is inversely proportional to the square root of their density. That is :

r  \: \infty   \: \sqrt{ \frac{1}{d} }

where r = rate of diffusion and d = density

 \frac{r1}{r2}  \:  =  \:  \sqrt{ \frac{d2}{d1} }  =  \sqrt{ \frac{M2}{M1} }

Where, M stands for molar mass of gas.

When two gases are compared at different pressure, then we may write :

r \:  \infty  \frac{p}{ \sqrt{m} } \:  or \: r \infty  \frac{p}{ \sqrt{d} }

Where p is pressure of the gas. Therefore,

 \frac{r1}{r2}  =  \frac{P1}{P2}  \sqrt{ \frac{d2}{d1} }  =  \frac{P1}{P2}  \sqrt{ \frac{M2}{M1} }

and, that's the required answer!

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