Derive the power in terms of voltage and current.
Answers
Answer:
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Explanation:
Ohm's law equation (formula): V = I × R and the power law equation (formula): P = I × V. P = power, I or J = Latin: influare, international ampere, or intensity and R = resistance. V = voltage, electric potential difference Δ V or E = electromotive force (emf = voltage).
Ohm's law equation (formula): V = I × R and the power law equation (formula): P = I × V. P = power, I or J = Latin: influare, international ampere, or intensity and R = resistance. V = voltage, electric potential difference Δ V or E = electromotive force (emf = voltage).Wattage or power P: watts W
Ohm's law equation (formula): V = I × R and the power law equation (formula): P = I × V. P = power, I or J = Latin: influare, international ampere, or intensity and R = resistance. V = voltage, electric potential difference Δ V or E = electromotive force (emf = voltage).Wattage or power P: watts WVoltage or volts E or V: volts V
Ohm's law equation (formula): V = I × R and the power law equation (formula): P = I × V. P = power, I or J = Latin: influare, international ampere, or intensity and R = resistance. V = voltage, electric potential difference Δ V or E = electromotive force (emf = voltage).Wattage or power P: watts WVoltage or volts E or V: volts VResistivity or resistance R: ohms Ω
Ohm's law equation (formula): V = I × R and the power law equation (formula): P = I × V. P = power, I or J = Latin: influare, international ampere, or intensity and R = resistance. V = voltage, electric potential difference Δ V or E = electromotive force (emf = voltage).Wattage or power P: watts WVoltage or volts E or V: volts VResistivity or resistance R: ohms ΩAmperage or current I: amperes, amps A
Answer:
»» Ohms Law and Power««
◆To find the Voltage, ( V ) [ V = I x R ] V (volts) = I (amps) x R (Ω)
◆To find the Current, ( I ) [ I = V ÷ R ] I (amps) = V(volts) ÷ R (Ω)
◆To find the Resistance, ( R ) [ R = V ÷ I ] R (Ω) = V (volts) ÷ I (amps)
◆To find the Power (P) [ P = V x I ] P (watts) = V (volts) x I (amps)