derive the relationship KE=1/2mv2 where M is the mass and V is the velocity of the body
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Kinetic Energy:-
The kinetic energy of a moving body is measured by the amount of work it can do before coming to rest.
Consider a body of mass 'm' moving with an initial velocity 'u'. When a force 'F' is applied on it , which displaces the object through a distance 's' and it's final velocity changes to 'v' and it produces an acceleration 'a'.
We know that,
v^2 - u^2 = 2as
s = v^2 - u^2/2a
Work done(W) = F × s
We know from Newton's second law of motion F = ma
W = ma × (v^2 - u^2/2a) (or)
W = 1/2 m(v^2 - u^2)
When the object starts from rest then it's initial velocity u = 0
Hence,
W = 1/2mv^2
This work done is stored in a form of KE
Therefore,
KE = 1/2 mv^2
Hope my answer helps you :)
Regards,
Shobana
The kinetic energy of a moving body is measured by the amount of work it can do before coming to rest.
Consider a body of mass 'm' moving with an initial velocity 'u'. When a force 'F' is applied on it , which displaces the object through a distance 's' and it's final velocity changes to 'v' and it produces an acceleration 'a'.
We know that,
v^2 - u^2 = 2as
s = v^2 - u^2/2a
Work done(W) = F × s
We know from Newton's second law of motion F = ma
W = ma × (v^2 - u^2/2a) (or)
W = 1/2 m(v^2 - u^2)
When the object starts from rest then it's initial velocity u = 0
Hence,
W = 1/2mv^2
This work done is stored in a form of KE
Therefore,
KE = 1/2 mv^2
Hope my answer helps you :)
Regards,
Shobana
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