Question

The product of two natural numbers is 15120 and their HCF is 6.FInd how many such pairs exist

Answer 1

MERRY CHRISTMAS FRIEND ✋✋✋

YOUR ANSWER IS.....

LET THE NUMBERS BE 6A AND 6B

6A × 6B = 15120

AB = 420

COPRIMES WITH PRODUCT 420 ARE ( 1 , 420 ) , ( 60 , 7 )

so there are two pairs

HOPE IT HELPS

Answer 2

Answer: 6

Step-by-step explanation:

Let the two natural numbers be a and b. HCF is 6 therefore the only common factor that the two numbers have is 6.

So, a =6x

b =6y

Here, x and y are co prime because if they had common factors then the HCF of a and b would be more than 6.

Now, product of the two natural numbers is 15120.

=> 6x6y = 15120

=> 36xy= 15120

=> xy= 420

Possible values of x and y such that they are co prime are:

• 15×28

• 7×60

• 3×140

• 4×105

• 6×70

• 30×14

Possible pairs are 6