Question

derive the third equation of motion from velocity time graph under uniform acceleration​

Answer 1

Answer:

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area of rectangle ACDO + area of DABC. [We make use of the identity a2 - b2 = (a + b) (a - b)] v2 - u2 = 2aS III equation of motion. (v + u)(v - u) = 2aS [using the identity a2 - b2 = (a+b) (a-b)] v2 - u2 = 2aS III Equation of Motion.

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