Derive the third equation of motion mathematically
Answers
Answered by
3
to derive V^2 - u^2= 2as or position velocity relationship
the distance travelled by the body is given by the area under velocity time graph.
distance travelled = to area of trapezium OABC
s= 1/2 OC (OA + BC )
= 1/2 t (u+v) vfrom equation (1) a= v-u/t , t=v-u/a
s = 1/2 (v-u) (v+u) the whole divided by a
2as = v^2-u^2
v^2-u^2= 2as
the distance travelled by the body is given by the area under velocity time graph.
distance travelled = to area of trapezium OABC
s= 1/2 OC (OA + BC )
= 1/2 t (u+v) vfrom equation (1) a= v-u/t , t=v-u/a
s = 1/2 (v-u) (v+u) the whole divided by a
2as = v^2-u^2
v^2-u^2= 2as
Similar questions