Question

Derive the three equations of motion by araphical method.​

Answer 1

Answer:

Derivation of Third Equation of Motion by Graphical Method

S = ½ (Sum of Parallel Sides) × Height.

S=(OA+CB)×OC. Since, OA = u, CB = v, and OC = t. ...

S= ½ (u+v) × t. Now, since t = (v – u)/ a. ...

S= ½ ((u+v) × (v-u))/a. Rearranging the equation, we get.

S= ½ (v+u) × (v-u)/a.

S = (v2-u2)/2a.

Answer 2

Derivation of Third Equation of Motion by Graphical Method.

• S = ½ (Sum of Parallel Sides) × Height.

• S=(OA+CB)×OC. Since, OA = u, CB = v, and OC = t. ...

• S= ½ (u+v) × t. Now, since t = (v – u)/ a. ...

• S= ½ ((u+v) × (v-u))/a. Rearranging the equation, we get.

• S= ½ (v+u) × (v-u)/a.

• S = (v2-u2)/2a.