Derive third equation of motion graphically and mathematically obtain second equation of motion from it.
(Please just don't derive and give third equation of motion please give answer only if you know how to solve whole question)
Nereida:
Ok
You don't do
I didn't told you to do
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see the graph and try to understand
displacement=area under graph
s=area of triangle ABC + area of rectangle ACDO
S=1/2*AC*CB+AO*OD
AC=t. CB=(V-u) AO=u. and. OD=t
s=1/2*t*(V-u)+u*t
s=1/2*t*at+it
s=1/2*a*t^2+u*t
s=it+1/2at^2
displacement=area under graph
s=area of triangle ABC + area of rectangle ACDO
S=1/2*AC*CB+AO*OD
AC=t. CB=(V-u) AO=u. and. OD=t
s=1/2*t*(V-u)+u*t
s=1/2*t*at+it
s=1/2*a*t^2+u*t
s=it+1/2at^2
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Is this after obtaining the derivation of we'd equation of motion graphically
yes
Oil
I meant oil
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Sorry
Thanks
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