Question

derive "v=u+at" equation of motion using calculus approach . a body starts from rest accelerating at 2 m/s² for 10s then moving with the velocity for another 10s calculate the distance travelled during this interval

Answer 1

Answer:

a = v-u / t

at = v - u

at + u = v

v = u + at

Distance travelled during first 10 s

using, s = ut + 1/2at²

were, u = 0 m/s

          a = 2 m/s²

          t = 10s

s = ut + 1/2at²

  = 0 m + 100 m

  = 100 m

Distance travelled during another 10 s

v = u + at

  = 0 m/s + 20 m/s

  = 20 m/s

using, 2as = v²-u²

v = 20 m/s

u = 0 m/s

a = 2 m/s²

2as = v²-u²

s = v²-u² / 2a

  = 400 m²/s² / 4 m/s²

  = 100 m

∴ The distance travelled during another 10s is 100 m