derive v² = u² + 2as
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First of all, you have to know the other two equations of motions :
1. V=u+at
2. S=ut+1\2at2
Now the derivation:
From the first equation we have :
- at=v−u
- t=v−u\a
Now putting the value of t in the second equation of motion:
- s=u(v−u\a)+1\2a(v−u\a)2
- s=uv−u2\a+a(v2+u2–2vu)\2a2
- s=uv−u2\a+(v2+u2+2vu)\2a
- s=(2uv−2u2+v2+u2–2vu)\2a
- 2as=v2−u2
- v2=u2+2as
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