derive v²-u² = 2as numerically .
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Answer:
From 1st equation of motion,
V = U + AT
Therfore, V - U = AT
We know that
S = (u+v/ 2 )×t
∴ s/t = u+v/t
∴ u+v = 2s / t
So Substituting eq1 and eq2,
(v - u ) (v + u) = at×2s/t
∴V² - U² = 2as
gjenagjena66:
Thanks..
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