Derminate the value of the log(1/16)base2
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pardon ask the question properly don't make spelling mistakes
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Step-by-step explanation:
Suppose log(1/16)base2 be x
then according to property of log
1/16=2^x
from here convert 1/16 into the form 2^some power so that you can equate both sides and find the value of x
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