Chemistry, asked by AkarshGRao3782, 1 year ago

Describe rutherford's gold foil experiment with labelled diageam

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Answered by Anonymous
5

In Rutherford experiment, fast moving alpha particle were made to fall on thin gold foil.


• This gold foil was about 1000 atoms thick.


• Alpha Particles are doubly charged Helium ions.


The following observations were made:


■ Most of the fast moving alpha particle passed straight through the gold foil.


■ Some of the fast moving alpha particle were deflected by making small angles.


■ Surprisingly one out of every 12000 particles appeared to be rebound.



Rutherford concluded from the alpha particle scattering experiment that :


• Most of the space inside the atom is empty because most of the fast moving alpha particle passed straight through the gold foil without getting deflected.


• Few of the fast moving alpha particle were deflected indicating the presence of a positive body inside the atom.


• A very small fraction of the alpha particle got renounced indicating that all the positive charge and mass is concentrated in a small volume within the atom.



Hope it helps..



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Answered by shobhasumer45
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Answer:the answer for s present the n the following picture

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