Question

Describe the hybridisation in case of Pcl5

Answer 1

ELEMENT:- P. CI5
ATOMIC NUMBER:- 15 17
ELECTRONIC CONFIGURATION IN
ORBITS:- 2,8,5. 2,8,7
VALENCE ELECTRON:-5. 7
TOTAL NO. OF VALENCE
ELECTRONS:- 5+5(7)=40
(/8)
= 5+0
=5.(sp3d.)

Answer 2

Answer:

In PCl5 molecule the central atom is P

15P – 1s2,2s2,2p6,3s2,3p3

excited state P — 1s2,2s2,2p6,3s1, 3p3, 3d1

no.of unpaired orbitals —>

 1  +  3  +  1 = 5

(s)    (p)    (d)              

so, it is sp3d Hybridisation.

Geometry of PCl5 molecule is trigonal bipyramidal. Bond angle is 90 and 120.