Describe the hybridisation in case of Pcl5
Answers
Answered by
7
ELEMENT:- P. CI5
ATOMIC NUMBER:- 15 17
ELECTRONIC CONFIGURATION IN
ORBITS:- 2,8,5. 2,8,7
VALENCE ELECTRON:-5. 7
TOTAL NO. OF VALENCE
ELECTRONS:- 5+5(7)=40
(/8)
= 5+0
=5.(sp3d.)
ATOMIC NUMBER:- 15 17
ELECTRONIC CONFIGURATION IN
ORBITS:- 2,8,5. 2,8,7
VALENCE ELECTRON:-5. 7
TOTAL NO. OF VALENCE
ELECTRONS:- 5+5(7)=40
(/8)
= 5+0
=5.(sp3d.)
Answered by
5
Answer:
In PCl5 molecule the central atom is P
15P – 1s2,2s2,2p6,3s2,3p3
excited state P — 1s2,2s2,2p6,3s1, 3p3, 3d1
no.of unpaired orbitals —>
1 + 3 + 1 = 5
(s) (p) (d)
so, it is sp3d Hybridisation.
Geometry of PCl5 molecule is trigonal bipyramidal. Bond angle is 90 and 120.
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