Describe the motion of a body which-
is accelerating at a constant
I rate of lom². If the body start
from rest how much distance
will it covers in 2 second? (20m)
Answers
Explanation:
You need to understand what acceleration means.
Acceleration is the change in your velocity (or speed) over time.
So if you are accelerating at a constant rate of 10 m/s^2, it means your speed is increasing by 10 m/s every second.
You start at rest, which means your starting speed is 0 m/s.
After 1 second, you have accelerated to a speed of 10 m/s
After 2nd second, you have accelerated by another 10 m/s => your current speed is 20 m/s.
So now, you know your final speed, 20 m/s.
Let’s get your average speed => (V1 + V2)/2 = (0 + 20)/2 = 10 m/s
speed = distance/time => 10 m/s = distance/2 s
=> distance = 10 m/s x 2 s = 20 m
U=Om/s
A=10m/s2
T=2s
D=?❓
S = ut +1/2 at^2
=0×2+1/2×10×2×2
=0+1/2×40
=20m Ans.
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