Question

Describe the path of
the projectile with
Diagram​

Answer 1

Explanation:

When a body is thrown with velocity making some angle with horizontal,it follows parabolic trajectory called projectile.

At general time ,velocity of the particle will be vcosθi^+(vsinθ−gt)j^

vx=vcosθ

vy=(vsinθ−gt)

X=vcosθt

Y=vsinθt−2gt2

Eliminating t,Y=vcosθvsinθx−2v2cos2θg×x2

Y=xtanθ−2u2cos2θg×x2 is called equation of train