Question

Describe the procedure to measure the diameter of a wire with the help of a screw gauge.


⭐Shortest and most correct answer will be marked brainliest!!!!⭐​

Answer 1

Answer:

Aim

To measure diameter of a given wire using screw gauge.

Materials Required

Screw gauge

Wire

Half-meter scale

Magnifying glass

Theory

What is least count?

Least count is given as:

Leastcount=pitchno.ofdivisionsoncircularscale

If a screw gauge has a pitch of 1 mm and 100 divisions on the circular scale then the least count is given as:

Leastcount=1mm100=0.01mm

How to take the linear scale reading?

Linear scale reading is taken by noting the mark on the linear scale which is close to the edge of the circular scale.

How to take circular scale reading?

Circular scale reading is taken by noting the division on the circular scale that coincides with the main scale reading.

Diagram

srew gauge measuring diameter of the wire

Procedure

Find the value of one linear scale division (L.S.D).

Determine and record the pitch and least count of the screw gauge.

To find the zero error, bring the plane face B and A near. Repeat and record this for three times. Record zero error as nil if there is no error.

Move face B away from face A. using a ratchet head R, move the face A towards face B lengthwise and stop when R turns without moving the screw.

Linear scale reading (L.S.R) is recorded by noting down the no.of visible and uncovered divisions of linear scale.

Let n be the no.of divisions of the circular scale lying on the reference line.

To measure diameter in a perpendicular direction, repeat steps 5 and 6 by rotating the wire to 90°.

For the entire length of wire, repeat steps 4,5,6 and 7 for five different positions and record the observations.

Find the total reading and also zero correction.

Take the mean of different values of diameter.

Using a half-meter scale, measure the length of the wire. Repeat this step three times and record the readings.

Observations

Determination of the least count of the screw gauge L.S.D = 1 mm

Number of full rotations given to screw = 4Distance moved by the screw = 4 mm

Hence, pitch p = 4 mm/4 = 1 mm

No.of divisions on circular scale = 100

Hence, the least count = 1 mm/100 = 0.01 mm = 0.001 cm

Zero error (i)… mm (ii)…. mm (iii)….. mm

Mean zero error (e) =… mmMean zero correction (c) = -e -…. mm

Table for diameter (D)

Answer 2

Explanation:

ANSWER I. English

Procedure

ProcedureFind the value of one linear scale division (

Determine and record the pitch and least count of the screw gauge.

Determine and record the pitch and least count of the screw gauge.To find the zero error, bring the plane face B and A near. ...

Determine and record the pitch and least count of the screw gauge.To find the zero error, bring the plane face B and A near. ...Move face B away from face A. ...

Determine and record the pitch and least count of the screw gauge.To find the zero error, bring the plane face B and A near. ...Move face B away from face A. ...Linear scale reading (L.S.R) is recorded by noting down the no. ...

Determine and record the pitch and least count of the screw gauge.To find the zero error, bring the plane face B and A near. ...Move face B away from face A. ...Linear scale reading (L.S.R) is recorded by noting down the no. ...Let n be the no.