Biology, asked by ramsunil2596, 1 year ago

Describe the stages in embryo development in a dicot plant

Answers

Answered by ShivPriya
0
heya !!!

DEVELOPMENT OF EMBRYO

The embryo develops at the micropylar end of the embryo was where the zygote is situated .

The zygote give rise first to pro - embryo and then , to globular , heart shaped mature embryo

A typical Zygote embryo consists of an embryobal axis and two cotyledons .

The portion of embryonal axis above the two cotyledons is called EPICOTYL.

It contains PLUMULE ( shoot tip )

The portion below the axis is called HYPOCOTYL , it contains the RADICLE ( root tip ) .

The root tip is covered by root cap .

hope it helps u dear ^_^
Answered by itsaddyhere
0

Development of a dicot embryo (i) Embryo formation starts after a certain amount of endosperm is formed. (ii) Zygote divides by mitosis to form a proembryo. (iii) Formation of globular and heart-shaped embryo occurs, which finally becomes horse shoe-shaped forms a mature embryo. (iv) In dicot plants, embryo consists of two cotyledons and an embryonal axis between them.(v) The portion of embryonal axis above the level of attachment of cotyledons is epicotyl and it terminates in the plumule. (vi) The portion of embryonal axis below the level of attachment of cotyledon is the hypocotyl, it becomes radicle (root tip).

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