design a PDA which recognize language L = a^n b^2n c^m where m,n>=1
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Design a non deterministic PDA for accepting the language L = {
Design a non deterministic PDA for accepting the language L = {a^n
Design a non deterministic PDA for accepting the language L = {a^nb^{2n} : n>=1} U {
Design a non deterministic PDA for accepting the language L = {a^nb^{2n} : n>=1} U {a^n
Design a non deterministic PDA for accepting the language L = {a^nb^{2n} : n>=1} U {a^nb^{n} : n>=1}, i.e.,
Design a non deterministic PDA for accepting the language L = {a^nb^{2n} : n>=1} U {a^nb^{n} : n>=1}, i.e.,L = {abb, aabbbb, aaabbbbbb, aaaabbbbbbbb, ......}
Design a non deterministic PDA for accepting the language L = {a^nb^{2n} : n>=1} U {a^nb^{n} : n>=1}, i.e.,L = {abb, aabbbb, aaabbbbbb, aaaabbbbbbbb, ......} U {ab, aabb, aaabbb, aaaabbbb, ......}
Design a non deterministic PDA for accepting the language L = {a^nb^{2n} : n>=1} U {a^nb^{n} : n>=1}, i.e.,L = {abb, aabbbb, aaabbbbbb, aaaabbbbbbbb, ......} U {ab, aabb, aaabbb, aaaabbbb, ......} In each string, the number of a’s are followed by double number of b’s or the number of a’s are followed by equal number of b’s.
Design a non deterministic PDA for accepting the language L = {a^nb^{2n} : n>=1} U {a^nb^{n} : n>=1}, i.e.,L = {abb, aabbbb, aaabbbbbb, aaaabbbbbbbb, ......} U {ab, aabb, aaabbb, aaaabbbb, ......} In each string, the number of a’s are followed by double number of b’s or the number of a’s are followed by equal number of b’s.Explanation –
Design a non deterministic PDA for accepting the language L = {a^nb^{2n} : n>=1} U {a^nb^{n} : n>=1}, i.e.,L = {abb, aabbbb, aaabbbbbb, aaaabbbbbbbb, ......} U {ab, aabb, aaabbb, aaaabbbb, ......} In each string, the number of a’s are followed by double number of b’s or the number of a’s are followed by equal number of b’s.Explanation –Here, we need to maintain the order of a’s and b’s.That is, all the a’s are are coming first and then all the b’s are coming. Thus, we need a stack along with the state diagram. The count of a’s and b’s is maintained by the stack.We will take 2 stack alphabets:
Design a non deterministic PDA for accepting the language L = {a^nb^{2n} : n>=1} U {a^nb^{n} : n>=1}, i.e.,L = {abb, aabbbb, aaabbbbbb, aaaabbbbbbbb, ......} U {ab, aabb, aaabbb, aaaabbbb, ......} In each string, the number of a’s are followed by double number of b’s or the number of a’s are followed by equal number of b’s.Explanation –Here, we need to maintain the order of a’s and b’s.That is, all the a’s are are coming first and then all the b’s are coming. Thus, we need a stack along with the state diagram. The count of a’s and b’s is maintained by the stack.We will take 2 stack alphabets:\Gamma = { a, z }
Design a non deterministic PDA for accepting the language L = {a^nb^{2n} : n>=1} U {a^nb^{n} : n>=1}, i.e.,L = {abb, aabbbb, aaabbbbbb, aaaabbbbbbbb, ......} U {ab, aabb, aaabbb, aaaabbbb, ......} In each string, the number of a’s are followed by double number of b’s or the number of a’s are followed by equal number of b’s.Explanation –Here, we need to maintain the order of a’s and b’s.That is, all the a’s are are coming first and then all the b’s are coming. Thus, we need a stack along with the state diagram. The count of a’s and b’s is maintained by the stack.We will take 2 stack alphabets:\Gamma = { a, z } Where,
Design a non deterministic PDA for accepting the language L = {a^nb^{2n} : n>=1} U {a^nb^{n} : n>=1}, i.e.,L = {abb, aabbbb, aaabbbbbb, aaaabbbbbbbb, ......} U {ab, aabb, aaabbb, aaaabbbb, ......} In each string, the number of a’s are followed by double number of b’s or the number of a’s are followed by equal number of b’s.Explanation –Here, we need to maintain the order of a’s and b’s.That is, all the a’s are are coming first and then all the b’s are coming. Thus, we need a stack along with the state diagram. The count of a’s and b’s is maintained by the stack.We will take 2 stack alphabets:\Gamma = { a, z } Where,\Gamma = set of all the stack alphabet
Design a non deterministic PDA for accepting the language L = {a^nb^{2n} : n>=1} U {a^nb^{n} : n>=1}, i.e.,L = {abb, aabbbb, aaabbbbbb, aaaabbbbbbbb, ......} U {ab, aabb, aaabbb, aaaabbbb, ......} In each string, the number of a’s are followed by double number of b’s or the number of a’s are followed by equal number of b’s.Explanation –Here, we need to maintain the order of a’s and b’s.That is, all the a’s are are coming first and then all the b’s are coming. Thus, we need a stack along with the state diagram. The count of a’s and b’s is maintained by the stack.We will take 2 stack alphabets:\Gamma = { a, z } Where,\Gamma = set of all the stack alphabetz = stack start symbol