design on the wall of a room consists of 8000 times of the shape of a parallelogram if the altitude and the base of a style is 10 centimetre and 4 centimetre respectively find the cost of polishing the design @ rupees 9.3decimeter
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Solution :-
We know that,
10 cm = 1 dm
Base = 4 cm = 4/10 dm = 0.4 dm
Altitude = 10 cm = 1 dm
Area of 1 tile = Base × Height
⇒ 0.4 × 1
= 0.4 dm²
Area of 1000 tiles = 1000 × 0.4
= 400 dm²
Cost of polishing = Rs. 9.5 dm²
Total cost of polishing = 9.5 × 400
= Rs. 3800
So, the total cost of polishing the design is Rs. 3800
Answer.
We know that,
10 cm = 1 dm
Base = 4 cm = 4/10 dm = 0.4 dm
Altitude = 10 cm = 1 dm
Area of 1 tile = Base × Height
⇒ 0.4 × 1
= 0.4 dm²
Area of 1000 tiles = 1000 × 0.4
= 400 dm²
Cost of polishing = Rs. 9.5 dm²
Total cost of polishing = 9.5 × 400
= Rs. 3800
So, the total cost of polishing the design is Rs. 3800
Answer.
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