Question

Determine an AP whose 3rd is 9 and when a5 is subtracted from a8 we get 6

Answer 1

in this a+ 2d=9..... (1)
(a+7d) -(a+4d) =6..... (2)
7d-4d=6
3d=6
d=2
put the value of d in (1) equation
a+2×2=9
a=9-4
a=5
so the ap is 5, 5+3, 5+2×3, 5+3×3
5, 8, 11, 14, and so on.


I hope this is useful