Question

determine an ap whose third term is 16 and when fifth term is subtracted from 7 term we get 12

Answer 1

let a be 1st term n d be the common difference

3rd term= a+2d=16
5th term= a+4d
7th term= a+6d

7th term - 5th term= 2d=12
=> d=6

hence a+2d=16
=> a=4

hence AP is 4, 10, 16, 22, 28, 34, 40......

Answer 2

4,10,16,22,28,...........................