Question

Determine an ap whose third term is 9 and when fifth term is subtracted from 8th term we get 6

Answer 1

HOPE THIS HELPS U. ..@MP. .

Answer 2

Here given

a3 = 9 ⇒ a + 2d = 9 ....(i)

a8 – a5 = 6

⇒ (a + 7d) – (a + 4d) = 6

⇒ 3d = 6

⇒ d = 2 ....(ii)  

Substituting (ii) in (i), we get

⇒ a + 2(2) = 9

⇒ a = 5

So, AP is 5, 7, 9, 11, .....