Determine an ap whose third term is 9 and when fifth term is substracted from 8th term we get 6
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Answer: 5, 7, 9, 11
Step-by-step explanation:
Here given
a3 = 9 ⇒ a + 2d = 9 ....(i)
a8 - a5 = 6
⇒ (a + 7d) - (a + 4d) =6
⇒ 3d = 6
⇒ d = 2 ....(ii)
Put (ii) in (i), we get
⇒ a + 2(2) = 9
⇒ a = 5
Hence, AP is 5, 7, 9, 11, .....
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