determine Ap whose 3rd term is 5 and 10th term is 9
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a3 = 5
a+2d = 5
a = 5-2d -----(1)
a10 = 9
a+9d = 9
5-2d+9d = 9
7d= 9 - 5
d = 4/7
a = 5-2d
a = 5-2(4/7)
= 35-8/7
= 27/7
a2 = a+d = 27/7+4/7
= 27+4/7
= 31/7
the AP is
27/7 , 31/7 , 5.. ...
here is ur answer
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