Question

Determine ap whose 3rd term is 9 and 5th tern is subtraced from 8th term we get 6

Answer 1

Step-by-step explanation:

Since the third term is 9

a+2d=9....eq.1

Acc.To the second condition,

(a+7d)-(a+4d)=6

a+7d-a-4d=6

3d=6

d=2

Putting d=2 in eq.1

a+2×2=9

a+4=9

a=5

Therefore first term is 5

Second term is 5+2=7

Third term is 7+2=9

Required ap = 5,7,9,...

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Answer 2

Step-by-step explanation:

t3=9,. t3=a+2d. therefore, a+2d=9----------(1)

also, t8-t5=6

t8=a +7d

t5=a +4d

therefore, a+7d-(a+4d)=6

a+7d-a-4d=6

3d=6

therefore d=6/3

d=2

put d=2 in eqn 1, a+4=9

therefore a=9-4=5

therefore the ap is t1=a= 5

t2=a+d=5+2=7

t3=a+2d = 5+2(2)=9

therefore the ap is 5,7,9,11