Question

determine ap whose a3 is16 and a7-a5 is 12​

Answer 1

Step-by-step explanation:

a3=a+2d=16. eq.1

a+6d-a-4d=12

2d=12

d=6

now putting value of d in eq1

a=4

AP 4,10,16....

Answer 2

Answer:

The AP is 4, 10, 16, 22,.........

Step-by-step explanation:

Given,

a3=16

=a+2d=16 ------->(i)

a7-a5=12

=a+6d-(a+4d)=12

=a+6d-a-4d=12

=2d=12

=d=6

Putting value of d in (i)

a+2(6)=16

a+12=16

a=4

∴The AP is a, a+d, a+2d, a+3d......

= The AP is 4, 4+6, 4+2(6), 4+3(6)......

∴The AP is 4, 10, 16, 22,.........

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