Determine constant of chemical equilibrium of the system А + 2В ⇄ 2С + 3D, if
concentrations of reagents were equal to А = 9.0 mol/l, В =15.8 mol/l and that for reaction
products С =27.5 mol/l and D =7.2 mol/l.
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Explanation:
Kf=d³xc²=7.2³x27.5²
Kb=axb²=9x15.8²
eq cons k=Kf/Kb=125.63
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