Question

determine degree of y(y-1) please answer fast it's urgent ​

Answer 1

Answer:

degree of discretion is 1

Answer 2

$y(y -1 ) \\ = {y}^{2} - y$

In standard form

$a {x}^{2} + bx + c$

Given equation can be written as

$1 {y}^{2} - 1y + 0$

the degree of a polynomial is the highest of the degrees of the polynomial's monomials (individual terms) with non-zero coefficients

Hence the degree is 2