Determine for what value of thitha,, 2 cos square thitha - 3 cos thitha +1 = 0
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▶HERE, IN THIS ANSWER, I AM HOLDING THE "THETAS" AS "x".
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2 cos² x - 3 cos x + 1 = 0
=> 2 cos²x - (2+1)cos x + 1 = 0
=> 2 cos²x - 2 cosx - cosx + 1 = 0
=> 2 cos x (cos x - 1) - 1 (cos x - 1) = 0
=> (cos x - 1) (2 cos x - 1) = 0
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EITHER :
cos x - 1 = 0
=> cos x = 1
=> cos x = cos 0°
=> x = 0°
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OR :
2 cos x - 1 = 0
=> 2 cos x = 1
=> cos x = 1/2
=> cos x = cos 60°
=> x = 60°
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Cutiepieshizuka:
Absolutely correct
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