Determine graphically the vertices of the triangle formed by the lines y=x 3y=x and x+y=8
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Answered by
191
Answer:
We are given that
y = x ...........(1)
3y = x ........(2)
x + y = 8 .......(3)
Solving Equation (1) and (2) we get
x = 0 and y = 0
So equation (1) and (2) meet at (0 , 0)
Similarly Now solving Equation (2) and (3).
Putting equation (2) in (3) we get
3y + y = 8
4y = 8
y = 2
Putting y = 2 in equation (2) we get
x = 6
So equation (2) and (3) meet at (6 , 2)
Now solving Equation (3) and (1).
Putting equation (1) in (3) we get
x + x = 8
2x = 8
x = 4
Putting x = 4 in equation (1) we get
y = 4
So equation (3) and (1) meet at (4 , 4)
Thus vertices's of triangle are (4 , 4) , (0 , 0) and (6 , 2)
The following graph illustrate clearly.
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Answered by
91
Hello buddy
Answer:
See the attached photo
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