Math, asked by ashwiniashwini486, 8 months ago

how to conclude about terminating and non terminating recurring decimals please give fastly this answer​

Answers

Answered by Shokman
0

Answer:

If the denominator is of the form 2^n*5^m, then that number will terminate.

If not, then it will be non terminating recurring

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Answered by vidhyabawane
0

Answer:

For example:

π = (3.141592653589793238462643383279502884197169399375105820974.....) is an example of non terminating decimal as it keeps on continuing after decimal point.

If a rational number (≠ integer) can be expressed in the form p2n×5m, where p ∈ Z, n ∈ W and m ∈ W, the rational number will be a terminating decimal. Otherwise, the rational number will be a nonterminating, recurring decimal.

For example:

(i) 58 = 523×50. So, 58 is a terminating decimal.

(ii) 91280 = 928×51. So, 91280 is a terminating decimal.

(iii) 445 = 432×51. Since it is not in the form \(\frac{p}{2^{n} × 5^{m}}\), So, 445 is a non-terminating, recurring decimal.

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