determine graphicaly the vertices of triangle the equations of whise sides are 2y-x=8,5y-x=14,-2x+y=1
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putting the value of x :- -2
2y-x=8
2y-2=8
2y=8+2
2y=10
y=10/2
y=5
then again putting the value of x :- -1
5y-x=14
5y-1=14
5y=14+1
5y=15
y=15/5
y=3
then again putting the value of y:- 3
-2x+y=1
-2x+3=1
-2x=1-3
-2x=-2
x=-2/-2
x=0
then draw on graph
x=0/y=3
x=-1/y=3
x=-2/y%=5
I hope it helps you
2y-x=8
2y-2=8
2y=8+2
2y=10
y=10/2
y=5
then again putting the value of x :- -1
5y-x=14
5y-1=14
5y=14+1
5y=15
y=15/5
y=3
then again putting the value of y:- 3
-2x+y=1
-2x+3=1
-2x=1-3
-2x=-2
x=-2/-2
x=0
then draw on graph
x=0/y=3
x=-1/y=3
x=-2/y%=5
I hope it helps you
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