Determine if the points (1, 5), (2, 3) and (-2, -11) are collinear.
Do this sum with
area of triangle = 1/2
|x1. y1|
|x2. y2|
|x3. y3|
|x1. y1|
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Solution :
Let A(-1,-1) = (x1,y1),B(0,1)=(x2,y2),
C(1,3)=(x3,y3) are vertices of
Triangle ABC.
Area of ∆ABC
=1/2|x1(y2-y3)+x2(y3-y1)+x3(y1-y2)|
=1/2|(-1)[1-3]+0[3-(-1)]+1[-1-1]|
= 1/2| (-1)(-2)+0+1(-2)|
=1/2| 2 -2 |
= 1/2 × 0
= 0
Therefore ,
Area of ∆ABC = 0,
A , B and C points are collinear.
.
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