Question

determine k if 4k+8, 2k 2 ​ +3k+6 and 3k 2 +4k +4 are the consecutive terms of an AP

Answer 1

i hope this will usful to u

Answer 2

These form an AP then,k - 
4k-6 - k-2 = 3k-2 - 4k+6
3k - 8 = -k + 4
3k + k = 4 + 8
4k = 12
k = 3