Question

Determine k so that 2k+2, 3k-1 and 5k+4 are three consecutive terms of A.P.

Answer 1

Answer:

-8

Step-by-step explanation:

Determine k so that 2k+2, 3k-1 and 5k+4 are three consecutive terms of A.P.

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If 3 numbers are consecutive terms of AP, then twice the middle number  is the sum of the others:

• 2(3k-1)=2k+2+5k+4
• 6k-2=7k+6
• 7k-6k=-2-6
• k=-8

Answer is k= -8