Math, asked by itssme6817, 1 year ago

Determine k so that 3k-2 2k2-5k+8&4k+3arethe three cosecutive terms of an ap


sinhaankitalko: what is 2k2???

Answers

Answered by amitnrw
0

Answer:

7 , 11 , 15 if k = 3

7/4  , 39/8  ,  8  if k = 5/4

Step-by-step explanation:

3k-2   ,  2k^2 - 5k+8  ,  4k+3

sum of 1st & 3rd tem = 2 * Second term

3k-2 + 4k+3 = 2 *(2k^2-5k+8)

7k +1 = 4k^2 -10k +16

4k^2 -17k +15 = 0

4k^2 -12k -5k + 15 = 0

4k(k-3) -5(k-3) = 0

(4k-5)(k-3) = 0

k = 5/4 or 3

Three terms with k =3

7 , 11 , 15

k = 5/4

7/4  ,  39/8    ,   8


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