Determine k so that 3k-2 2k2-5k+8&4k+3arethe three cosecutive terms of an ap
sinhaankitalko:
what is 2k2???
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Answer:
7 , 11 , 15 if k = 3
7/4 , 39/8 , 8 if k = 5/4
Step-by-step explanation:
3k-2 , 2k^2 - 5k+8 , 4k+3
sum of 1st & 3rd tem = 2 * Second term
3k-2 + 4k+3 = 2 *(2k^2-5k+8)
7k +1 = 4k^2 -10k +16
4k^2 -17k +15 = 0
4k^2 -12k -5k + 15 = 0
4k(k-3) -5(k-3) = 0
(4k-5)(k-3) = 0
k = 5/4 or 3
Three terms with k =3
7 , 11 , 15
k = 5/4
7/4 , 39/8 , 8
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