Question

Determine the ap whose fourth term is 18 and the difference of the nine term from the 15 term is 30

Answer 1

Answer:

Step-by-step explanation:

Given:-

a↓4=18

a+3d=18. ........eq(1)

A.Q.,

a+14d-(a+8d)=30

a+14d-a-8d=30

6d=30

d=5

Putting value of d in eq(1),we get

a+3(5)=18

a+15=18

a=3

Therefore,

a+d=3+5

=8

a+2d=3+2(5)

=13

a+3d=3+3(5)

= 18

Hence, A.P so formed is 3,8,13,18......