Question

Determine k so that 3k-2,4k-6,k+2...are in AP

Answer 1

Answer:

It is given that (3k -2), (4k – 6) and (k +2) are three consecutive terms of an AP

Hence the value of k is 3

Answer 2

Answer:

k=3

Step-by-step explanation:

a1=3k-2        a2=4k-6       a3=k+2

d=a2-a1=a3-a2

 =4k-6-(3k-2)=k+2-(4k-6)

 =4k-6-3k+2=k+2-4k+6

 =   k-4         =   -3k+8

 =   k+3k      =   8+4

 =   4k          =   12

 =              k = 3