Determine k so that 8k +4,6k-2,and-2k7 are three consecutive terms of an A.P
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Answer:
(6k-2)-(8k-4)=(2k-7)-(6k-2)
6k-2-8k+4 = 2k-7-6k+2
12k-10k = -7
2k = -7
k = -7
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