Determine 'k' so that :
(i) k + 2, 4k – 6, 3k - 2
(ii) 8k + 4, 6k - 2, 2k - 7
are the three consecutive terms of an A.P.
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Answer:
We know that
2b = a + c
2( 4k - 6) = k+2 + 3k - 2
8k - 12 = 4k
4k = 12
k = 3.
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