Determine K so that k 2 +4k+ 8 ,2k 2 +3k+ 6 and3k 2 +4k+ 4 are three consecutive terms of AP.
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we know according to AP :-common difference is constant
i.e.
=>2k^2+3k+6-4k-8=3k^2+4k+4-2k^2-3k-6
=>k^2-2k=0
=> k (k-2)=0
=> k=0,2
i.e.
=>2k^2+3k+6-4k-8=3k^2+4k+4-2k^2-3k-6
=>k^2-2k=0
=> k (k-2)=0
=> k=0,2
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