Determine k so that k2+4k+8determine k so that k2+ 4k + 8, 2k2 + 3k + 6, 3k2 + 4k + 4 are three consecutive terms of an ap
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for a,b,c to be in a.p
2b=a+ c
here a ,b, and c is given in terms of k and k^2.
Just put them in the eqn and solve quadratic to value/s of k
2b=a+ c
here a ,b, and c is given in terms of k and k^2.
Just put them in the eqn and solve quadratic to value/s of k
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