Math, asked by prashantjaju38, 10 months ago

Determine k so that the equation 2x

2 – kx + 1 = 0 have concident roots​

Answers

Answered by varshaASK
1

Compare given Quadratic equation 2x²-kx+k=0 with ax²+bx+c=0, we get

a = 2,b = -k , c = k,

Discriminant (D)=0

[ Given roots are equal ]

=> b²-4ac=0

=> (-k)²-4×2×k=0

=> k²-8k=0

=> k(k-8)=0

=> k = 0 or k=8

Therefore,

value of k=0 or k=8

Hope this helps u

Answered by sudee777
1

ANSWER: k = 22

Given 2x^2 - kx + 1

comparing with ax^2 + bx + c = 0

a = 2 b = -k c = 1

discriminant d = 0

then

b^2 - 4ac = 0

(-k)^2 - 4(2)(1) = 0

k^2 - 8 = 0

k^2 = 8

k = √8

k =√4*2

k = √4*√2

k = 2√2

Similar questions